Parallel and Spherical Plate Capacitor

A parallel plate capacitor of capacitance $C$ is charged to a potential $V$ by a battery. $Q$ is the charge stored on the capacitor. Without disconnecting the battery, the plates of the capacitor are pulled apart to a larger distance of separation.

What changes will occur in each of the following quantities? Will they increase, decrease or remain the same? Give an explanation in each case.

(a) Capacitance

(b) Charge

(c) Potential difference

(d) Electric field

(e) Energy stored in the capacitor

A capacitor consists of two parallel plates, with an area of cross-section of $0.001 {\mathrm{m}}^2$, separated by a distance of $0.0001 \mathrm{m}$. If the voltage across the plates varies at the rate of ${10}^8 \mathrm{V}/\mathrm{s}$, determine the value of displacement current through the capacitor.

A parallel plate capacitor is of area $6\mathrm{ }{\mathrm{cm}}^2$ and a separation $3\mathrm{ }\mathrm{mm}$. The gap is filled with three dielectric materials of equal thickness (see figure) with dielectric constant $K_1=10, K_2=12$ and $K_3=14.$ The dielectric constant of a material which when fully inserted in above capacitor, gives same capacitance would be:

Two parallel plate capacitors are constructed one by a pair of iron plates and the second by a pair of copper plates of same area and same spacing. Then -

Bending of electric field lines near the edges of the capacitor plate is called the 'fringing of field'. The cause behind it is:

A voltage is applied between the plates of a parallel plate capacitor filled with a dielectric between the plates. Considering the fringing of field, which of the following statement is wrong?

What do you mean by fringing of a field?

A $600 \mathrm{\mu F}$ capacitor is charged by $250 V$ battery. The capacitor is disconnected from battery and connected to another $600 \mathrm{\mu F}$ capacitor. Energy of the system in joule is 

A $600 \mu F$ capacitor is charged by $250 V$ battery. Magnitude of electrostatic energy stored in capacitor in joule is 

What is the electric field between the plates of a charged parallel plate capacitor with surface charge density ${\mathrm{\sigma }}_0$ on plates?

On assuming earth as a spherical conductor what will be its capacitance?

If area of one plate of a parallel plate capacitor is halved then can the device be called a capacitor?

The radii of two spherical conductors are in ratio $1:2$. The ratio of their capacitance is.

The radius of plate used in a parallel plate capacitor is $10 \mathrm{cm}$. If the plate separation is $10 \mathrm{cm}$ determine the capacitance of this capacitor for air medium.

$125$ droplets are charged to $200 \mathrm{V}$ potential. These droplets are combined to make a single drop. Calculate the potential of big drop and change in potential energy.

Consider two metallic spheres of radius $0.05 \mathrm{m}$ and $0.10 \mathrm{m},$ each having a $75 \mathrm{\mu F}$ charge. On connecting these spheres by a conducting wire find the amount of charge flown.

Consider two metallic spheres of radius $0.05 \mathrm{m}$ and $0.10 \mathrm{m}$ each having a $75 \mathrm{\mu F}$ charge. On connecting these spheres by a conducting wire find the common potential.

Calculate the capacitance of a conducting sphere of radius $10 \mathrm{cm}$ situated in air. How much charge is required to raise to a potential of $1000 \mathrm{V}$?

Write the working principle of a parallel plate capacitor. On what factors, the capacitance of a parallel plate capacitor depends?

In a parallel condenser the radius of each circular plate is $12 \mathrm{cm}$ and the distance between the plates is $5 \mathrm{mm}$. There is a glass slab of $3 \mathrm{mm}$ thick and of radius $12 \mathrm{cm}$ with dielectric constant $6$ between its plates. The capacity of the condenser will be